Data Session 4: Solutions

A B C D E
Homework

Solutions for Session 4, Part D

See solutions for Problems: D1 | D2 | D3

Problem D1

Since the median and quartiles require separating the data into halves that are larger or smaller than a central value, it is necessary to order the data. If the data are unordered, it is much more difficult to find the value that splits the list into two equal groups.

<< back to Problem D1

Problem D2

To create a box plot, first create a Five-Number Summary for each data set:

a. For Brand A, here is the Five-Number Summary:
Min = 23
Q1 = 27
Med = 29.5
Q3 = 32
Max = 39

Here is the box plot:

Brand A box plot

b. For Brand B, here is the Five-Number Summary:
Min = 17
Q1 = 25
Med = 26
Q3 = 29
Max = 30

Here is the box plot:

Brand A box plot

<< back to Problem D2

Problem D3

Placing the box plots side by side clearly shows that a large number of Brand A boxes have more raisins than Brand B boxes. The interquartile range is a little wider for Brand A, and the top 25% of Brand A boxes are all higher than Brand B's maximum. This suggests strongly that Brand A, on average, has more raisins in a typical box than Brand B.

<< back to Problem D3

Session 4 | Notes | Solutions | Video