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Solutions for Session 2, Part D
See solutions for Problems: D1 | D2 | D3 | D4 | D5 | D6| D7
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Problem D2 | |
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You would find the median in the same way, by finding the value that has an equal number of values above and below it. You could still do this by removing the highest and lowest values in the data set until only the median remains.
<< back to Problem D2
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Problem D3 | |
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The ordered list is 63, 68, 70, 70, 72, 72, 75, 82, 84. The value in the center of this list is 72, which makes it the median.
<< back to Problem D3
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Problem D4 | |
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The median is the ninth number in the ordered list, which, in this case, is 6.
<< back to Problem D4
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Problem D5 | |
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The second value is 26, since its position (2) is higher than the cumulative frequency of 25 (1), but not higher than the cumulative frequency of 26 (3).
<< back to Problem D5
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Problem D7 | |
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We know that the median is in the ninth position (of 17 total boxes), which falls between the cumulative frequency of 27 (6) and 28 (11); therefore, the median is 28.
<< back to Problem D7
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