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Solutions for Session 6, Part D
See solutions for Problems: D1 | D2 | D3 | D4 | D5 | D6 | D7 | D8 | D9 | D10 | D11
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Problem D1 | |
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The resulting graph is a line. It has a slope of 2, and passes through the points (0, -3), (1, -1), (2, 1), and many others.
<< back to Problem D1
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Problem D3 | |
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Pick two points: for example, (-1, -5) and (3, 3). The rise is the change in y, which is 3 - (-5) = 8. The run is the change in x, which is 3 - (-1) = 4. Then the slope, which is rise/run, is 8/4 = 2. Note that the slope, 2, is represented in the equation as the number that x is multiplied by.
<< back to Problem D3
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Problem D5 | |
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This point is the intersection of the lines, and the solution to the system of equations y = 2x - 1 and y = -x + 5. This also means that x = 2 is the solution to the balance equation 2x - 1 = -x + 5.
<< back to Problem D5
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Problem D7 | |
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The graphs intersect at the point (1, 2), which is the solution to the system. The solution to the balance equation 4x - 2 = 5x - 3 is x = 1.
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Problem D8 | |
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The graph is bowl-shaped, a parabola. Its lowest point is (0, 0). This point is the lowest because multiplying a number other than zero by itself always results in a positive number.
<< back to Problem D8
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