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From: Larry, Rita, Joe, Garrett (wintercr@xyz.net)
Date: Mon Mar 11 2002 - 15:03:24 EST
Next message: Stephen Cicioni: "RE: [Channel-talkalgebra] Session 8 Problem B10"
In Session 8, Problem B10 we are asked to make a graph of the function suggested by problem B8, xy=3. We are prompted to choose 5 positive and 5 negative numbers for our T table x values. The negative numbers would yield negative y values because a neg. times a neg. equals a positive. (The functions says xy=3 not -3 or any other number.) I am wondering why the graph shown in the solution section only shows the function in quadrant I when there is a reflection of that line in quadrant III, if we are to graph the negative numbers on our T charts as well. Am I misinterpretting something?
Thank-you,
Rita Pfenninger
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